Classification Puzzle Test for Bank Exam

Time and Work Tricks for Bank Po

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Time and Work Tricks for Bank Po

Time and Work Tricks for Bank Po exam

If a man A can do a piece of work in m days

Then the piece of work done by A in 1 day = 1/m

 

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Now suppose A can do a piece of work in x days

B can do the same work in y days

1 day work of A = 1/x

1 day work of B =1/y

1 day work of A and B = 1/x + 1/y

                                    = (y + x) / xy

A and B can do the work in xy/ (x + y) days

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And C can do a work in z days

Then 1 day work of A =  1/x

1 day work of B = 1/y

1 day work of C = 1/z

1 day work of A, B and C together = 1/x + 1/y + 1/z

                                                     = (yz + zx + xy)/ xyz

Then A, B and C can finish the work together in xyz/ (xy + yz + zx) days

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Time and work Tricks for Bank Exam

Total work done = number of persons number of days

Suppose M1persons can do a work in D1days and M2persons can do the same work in D2days

Then total work done by M1persons  = M1D1

Total work done by M2persons = M2D2

But the work done by both group of persons is same

M1D1 = M2D2

Question on SSC CGL exam

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Suppose M1 persons can do W1 works in D1 days and M2 persons can do W2 works in D2 days

Then  M1.D1. W2 = M2. D2 .W1

Efficiency

If A can do a work in x days and B can do a work in y days

Then 1 day of work = 1/x

1 day work of B = 1/y

Ratio of efficiency = 1/x : 1/y

                            = y : x

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Ratio of efficiency of A and B = Y : X

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Suppose A builds a building in x days

B builds the same building in y days

And C breaks the same building in z days

1 day work of A = 1/x

1 day work of B = 1/y

1 day work of C = – 1/z ( this is negative because C breaks the building i.e. C works negative for us)

1 day work of all together = 1/x + 1/y – 1/z

                                        = (yz + zx – xy) / xyz

A,B and C will finish the work in xyz / (yz + zx – xy) days

Some important ticks

Time and work Tricks for Bank Exam

1. If A and B together can do a work in x days, B and C together can do it in y days and C and A can do the same work in z days, then in how many days can A, B and C together complete the work ?

No. of days = 2xyz/xy+yz+zx

2. If A, B and C together complete a work in x days, while any two of them complete the work in y and z days respectively, then in how many days the third complete the work ?

= xyz/yz-x(y + z)

3.  If A and B together can do a work in x days, B and C together can do it in y days and C and A can do the same work in z days, then in how many days can A, B and C alone complete the work ?

A =  2xyz/xy+yz-zx

B = 2xyz/-xy+yz+zx

C = 2xyz/xy-yz+zx

4. A can do complete a work in x days, but after y days A leave and remaining work completed by B in z days. In how many days can B alone do the complete work ?

= (xz/x-y)

5. If A is n times efficient as B  and both together complete a work in x days, then A and B alone complete the work in

A= (n+1/n) × days

B= (n+1) × days

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