## Mensuration questions for Bank Po

# Mensuration questions for Bank Po

Mensuration questions for Bank Po, IBPS PO,SBI and other governents exam

**Area: **area of a bounded figure is the space covered by it.

**Perimeter: **The length of the boundary of a closed figure is called perimeter

**Triangle: **A plane figure bounded by three straight lines is called a triangle

**Area of a triangle = ****1/****2 **base height = **1/****2 **CDAB

√s(s-a) (s-b) (s-c)

And s = a + b + c/2

Where a, b, c are the lengths of the sides of triangle

**Equilateral triangle** if all the three sides of a triangle are equal , then there is an equilateral triangle

Area of an equilateral triangle = √3/4 a^{2}

Perimeter of an equilateral triangle with side a = 3a

**Isosceles triangle** if at least two sides of a triangle are equal, there is a isosceles triangle

Area of isosceles triangle = a/4 √4b^{2} – a^{2}

And height of isosceles triangle, h = √b^{2} – a^{2/}4

Perimeter of isosceles triangle = 2b + a

**Square:**

Area of a square = (side)^{2}= a^{2} or

d^{2}/2 where d is the diagonal of a square

Perimeter of a square = 4a

Diagonal of a square = √2a

Area of a path which is outside of a square of uniform width x = 4x^{2}+ 4ax

Area of a path which is inside of a square of uniform width x = 4ax – 4x^{2}

Perimeter of a path which is outside of a square of uniform width x = 4(a + 2x)

Perimeter of a path which is inside of a square of uniform width x = 4(a- 2x)

## Mensuration questions for Bank Po

**Rectangle: **

Area of a rectangle = lb, where l is the length of a rectangle and b is the breadth of a rectangle

Perimeter of a rectangle = 2(l + b)

Diagonal of a rectangle, d = √l^{2} + b^{2}

Area of a path which is outside of a rectangle of uniform width x =4x^{2}+2lx + 2bx

Area of a path which is inside of a rectangle of uniform width x = 2lx + 2bx – 4x^{2}

Perimeter of a path which is outside of a square of uniform width x = 2(l + b + 2x)

Perimeter of a path which is outside of a square of uniform width x = 2(l + b – 2x)

Top SSC Coaching in New Delhi

**Parallelogram: **

Area of parallelogram = 1/2 base×height = 12×b×h

**Rhombus:** it is a parallelogram whose all sides are equal

Its diagonal bisect each other at right angle.

Area of rhombus = 1/2 product of diagonals = 1/2×d_{1×}d_{2 }or

Area = 1/2×b×h

Where b is the side of rhombus, h is the height and d_{1},d_{2 }are the diagonals of the rhombus

Perimeter of rhombus = 4b

Side of rhombus = ( d1/2)^{2} + ( d_{2/}2)^{2}

**Trapezium:**

Area of trapezium = 1/2 height×(sum of parallel sides)

Median of trapezium = 1/2×(sum of parallel sides)

Median is the line segment joining the midpoints of non parallel side

This Question asked by Best Bank Coaching

**Circle:**

Area of a circle= π r^{2}

Diameter (d) = 2r

Circumference = 2πr

Area of a sector = θ/360 r^{2}

Length of arc = 360 2r

Area of the ring or circular path = (R+r) (R-r)

**Cube:**

Volume of a cube = a^{3}

Diagonal of a cube = √3a

Surface area of a cube = 6a^{2}

Area of four walls = 4a^{2}

**Cuboid:**

Volume of a cuboid = l×b×h

Diagonal of a cuboid = √l^{2}+ b^{2}+h^{2}

Surface area of a cuboid = 2(lb + b

Volume of a cylinder = πr^{2}h

Curved surface area = 2πrh

Total surface area = 2r(r + h)

Direct and Indirect Speech 1 English section

**Cone: **

Volume of a cone = 1/3 πr^{2 }h

Curved surface area = rl

Total surface area = πr (l + r)

Slant height = √h^{2}+ r^{2}

**Sphere: **

Volume of a sphere = 4/3 π r^{3}

Surface area = 4π r^{2}

**Hemisphere:**

Volume of a hemisphere = 2/3 r^{3}

Curved surface area = 2π r^{2}

Total surface area = 3π r^{2}

**Frustum of a cone**

Volume = 1/3πh(r^{2}+R^{2}+ r.R)

Surface area = π(r + R)√(R -r)^{2}+h^{2}

Total surface area = π(r + R)√(R -r)^{2}+h^{2} + πr^{2} +πR^{2}

Slant height, l = √(R -r)^{2}+h^{2}

**Right pyramid**

Volume of a pyramid = 1/3×(area of the base)×height

Lateral surface area of a pyramid = 1/2 ×(perimeter of base) × slant height

Total surface area of a pyramid = lateral surface area + area of the base

**Regular tetrahedron** it is a polyhedron with four equilateral triangle faces

Let the edge of a regular tetrahedron is a

Volume = √2/12 a^{3}

Lateral surface area = 3√3/4 a^{2}

Total surface area = √3a^{2}

**Relation between edges, vertices and faces of a polyhedron**

**Faces + edges = vertices – 2**

### Related Posts

« Sequence and Series Questions for Bank Po Simple Interest and Compound Interest for IBPS PO »